Customers of the key refining company charge an average of $70 per month. the distribution of amounts charged is approximately normal, with a standard deviation of $10. what is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83

0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $70

Standard Deviation, σ = $10

We are given that the distribution of amounts charged is a bell shaped distribution that is a normal distribution.

Formula:

P(customer charged between $70 and $83)

Thus, 0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: