The manager of a gas station has observed that the times required by drivers to fill their car's tank and pay are quite variable. in fact, the times are exponentially distributed with a mean of 7 minutes. what is the probability that a car can complete the transaction in less than 4 minutes?

0.4353 = 43.53%

Step-by-step explanation:

The times are exponentially distributed, so let's call n the mean, and x the time of transaction. The times of the transaction occurs in a certain time is:

So, the probability that a car complete the transaction in less than 4 minutes, is 1 less the times it does it at 4 minutes:

P = 1 -

P = 0.4353

P = 43.53%

yes

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