Your school sells yearbooks every spring. the total profit p made depends on the amount x
the school charges for each yearbook. the profit is modeled by the equation p= -2x^2 + 70x
+ 520. what is the smallest amount in dollars the school can charge for a yearbook and
make a profit of at least $1000?

x=25.63

Step-by-step explanation:

turn p into 1000.

1000= -2x^2+70x+520

Subtract 520 from both sides

1000-520= 480

480= -2x^2+70x

Apply the quadratic formula, and x=25.63

So you have to charge at least $25.63

Step-by-step explanation:

The given expression is

Where is profit and is money.

Now, with the restriction of making profits of at least $1000, the expression would be

We need to multiply the inequality by -1/2,

Now we solve the quadratic expression

Solving with a calculator, the numbers that satisfy the quadratic expression are approximately and

The image attached shows the graph solution of this inequality.

Therefore, the smallest solution to make a profit of at least $1000 is $9.361.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet