What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2plus or minus 2 startroot 5 endroot x = ±6plus or minus 6 startroot 3 endroot x = ±5plus or minus 5 startroot 2 endroot no real solution

Option 4 -  

Step-by-step explanation:

Given : Quadratic equation

To find : What are the solution(s) to the quadratic equation ?

Solution :

Step 1 - Write the quadratic equation,

Step 2 - Subtract 50 both side,

Step 3 - Taking root both side,

Therefore, the solution of the equation is

So, option 4 is correct.

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot on ed!!!

Step-by-step explanation:

answer: f = 32.2m

step-by-step explanation: that is the answer

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb