Let x denote the proportion of allotted times that a randomly selected student spends working on a certain test. suppose the pdf of x isf(x; θ) = { θxθ-1 when }{ 0 otherwise }where θ 0. a random sample of ten students yields datax1= .92x2= .79x3= .90x4= .65x5= .86x6= .47x7= .73x8= .97x9= .94x10= .77note: the sum of xi is 8, and the product ∏xi = .088a.) use the method of moments to obtain an estimator of θ, and then compute the estimate for this data. b.) obtain the maximum likelihood estimator of θ, and then compute the estimate for the given data.

i have no clue what you just said. write a question in english?

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4