Apoll was taken of 588 residents in a county. the residents sampled were asked whether they think their local government did a good job overall. 490 responded ""yes"". let p denote the proportion of all residents in that county who think their local government did a good job. construct a 95% confidence interval for p: round off to two decimal places.

[472.29, 507.71]

Step-by-step explanation:

The proportion is  

490/588 = 0.8333

The mean can be estimated as  

= 490  

and the standard deviation can be approximated with

= 9.037

and we just need to find two values a and b such that the area under the Normal curve of mean 490 and standard deviation 9.037 between a and b equals 95% = 0.95

With the help of a spreadsheet we can easily find these values which are

a = 472.288

b = 507.712

and the interval we are looking for, rounded to 2 decimals, is [472.29, 507.71]

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

answer: i'm not sure

step-by-step explanation: