Can i get some on this question?

which point is in the solution set for y < x+2? explain your answer.

question 3 options:

(0, 2) because when you graph y < x+2, it is a point on the boundary line.

(-2, 0) because when you graph y < x+2, it is the x-intercept of the boundary line.

(1, 4) because when you graph y < x+2, it is a point that lies above the boundary line.

(2, 1) because when you graph y < x+2, it is a point that lies below the boundary line.

instagram is better than go there instead lol

step-by-step explanation:

2

step-by-2step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

34

step-by-step explanation: