Need asap ! six times the sum of two consecutive integers is eight more than five times the
larger integer. find the integers.
the first integer is
the second integer is

The first integer is  1

The second integer is 2

Step-by-step explanation:

Given that two numbers are consecutive:

Let the integers be:

First integer = x

Second Integer = x +1

Now according to given conditions the equation will be:

Final equation:

12x + 6 = 5x +13

Taking terms with x on left and others on right side

12x - 5x = 13 - 6       (signs of transferred terms will be changed)

7x = 7

Dividing both sides by 7 we get:

x = 1

So,

The first integer is  1

The second integer is 1+1 =2

I  hope it will help you!

the correct answer is c) 2.