Alarge box contains 10,000 ball bearings. a random sample of 120 is chosen. the sample mean diameter is 10 mm, and the standard deviation is 0.24 mm. true or false: a. a 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 ± (1.96)(0.24)/√ 120. b. a 95% confidence interval for the mean diameter of the 10,000 bearings in the box is 10 ± (1.96)(0.24)/√120. c. a 95% confidence interval for the mean diameter of the 10,000 bearings in the box is 10 ± (1.96)(0.24)/√10,000.

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

i pretty sure it is