Suppose that the objective function changes to maxz = 3x1 + (7 + ∆)x2 + 5x3. write down the new simplex tableau in which x3 and x2 are basic variables. for what range of ∆ does that tableau show an optimal solution? write down an optimal solution and a formula for the optimal value for ∆ in that range. does ∆ = 4 belong to that range? find an optimal solution and the optimal value for ∆ = 4.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars