Given m||n, find the value of x.
(6x+10)
(5x+28)

Simplifying

6x + 10 = 5x + -28

Reorder the terms:

10 + 6x = 5x + -28

Reorder the terms:

10 + 6x = -28 + 5x

Solving

10 + 6x = -28 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

10 + 6x + -5x = -28 + 5x + -5x

Combine like terms: 6x + -5x = 1x

10 + 1x = -28 + 5x + -5x

Combine like terms: 5x + -5x = 0

10 + 1x = -28 + 0

10 + 1x = -28

Add '-10' to each side of the equation.

10 + -10 + 1x = -28 + -10

Combine like terms: 10 + -10 = 0

0 + 1x = -28 + -10

1x = -28 + -10

Combine like terms: -28 + -10 = -38

1x = -38

Divide each side by '1'.

x = -38

Simplifying

x = -38

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.