Idon’t know how to graph it. letter c.

Your equation for A is correct.

Part B

To find the x-intercepts, let y = 0 in the equation shown in part A and solve for x.

To find the y-intercept, let x = 0 in the equation shown in part A and solve for y.

So, do the math.

45x + 30y = 1350

Let x = 0

45(0) + 30y = 1350

30y = 1350

y = 1350/30

y = 45

The y-intercept is the point (0, 45).

Let y = 0

45x + 30(0) = 1350

45x = 1350

x = 1350/45

x = 30

The x-intercept is the point (30, 0).

The x-intercept represents where the graph crosses the x-axis and the y-intercept represents where the graph crosses the y-axis.

Part C

To graph this linear equation, plot the x and y intercepts on the xy-plane given and connect the points with a straight line.

Look: plot the points (30, 0) and (0, 45) and connect the points with a straight line. This will yield the graph of the linear equation shown in Part A.

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