3. a logo is designed as shown in the diagram below. a sector oab, of angle 60° and radius 20cm
is drawn. the perpendicular bd is dropped from b to oa and a quarter circle ead centered at d
is drawn. find the area of the shaded part, bae. bd is a perpendicular bisector of oda. area of
sector r20.
hint: subtract the sum of area of triangle and quarter circle from area of sector. :
2oum
e

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.