You are working at a bank and doing resource planning. you think that there should be six tellers working in the bank. tellers take 15 minutes per customer with a standard deviation of 5 minutes. on average one customer arrives every three minutes according to an exponential distribution. a. on average how many customers are waiting in line? b. on average how long would a customer spend in the bank?

Lq = 1.680

time taken by customer 20.03 min

Step-by-step explanation:

Given data:

m = 6

a = 3 min

p = 15 minutes

CVa = 1

Number of customer waiting in line =

Lq = 1.679158

Lq = 1.680

FROM QUENNING FORMULA WE GET Tq =  5.039

so, time taken by customer = 5.039 + 15 = 20.03 min

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: