Consider the system of equations -10x1 + 4x2 = 0 15x1 - 6x2 = 0 as you did in the previous exercise, enter the corresponding matrix c and column vector d into matlab. then type in > > x = c\d note the strange output. include it in your write-up. now go ahead and solve this system by hand. how many free variables do you have in your solution? based on your answer, can you explain why you got the error message when trying to use the command x = c\d?

the 3rd on is correct

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a