Can a quadratic polynomial equation with real coefficients have one real solution and one complex solution? if so,
give an example of such an equation. if not, explain why not.
recall from algebra ii that every quadratic expression can be written as a product of two linear factors, that is,
ax^2 + bx + c = a(x − r1)(x − r2),
where rr1 and rr2 are solutions of the polynomial equation ax^2 + bx + c = 0.

No

Step-by-step explanation:

We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.

quadratic equation is given by

It can be written as  the product of linear factors

Where are solutions of the given  polynomial equation.

No , a quadratic polynomial equation can not  have one real solution and one complex solution because complex root are always in paired not a single.

A quadratic equation have two roots only.

If a quadratic equation have complex root then the equation have both complex root .

If  a equation have real root then it have both real.

Therefore, a quadratic equation can not have one real and one compelx solution.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: