If (a^3+27)=(a+3)(a^2+ma+9) then m equals

If the expression (a³+27)=(a+3)(a²+ma+9), then the value of m is; m = -3.

From the question; (a^3+27)=(a+3)(a^2+ma+9).

To fund the value of m; we must first expand the right hand side of the equation so that we have;

By collecting like terms, we are left with the expression;

By dividing through by a, we have;

By collecting like terms, we have;

And, finally by dividing both sides of the equation by (a+1);. we have;

m = -3.

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m = - 3

Step-by-step explanation:

a³ + 27 ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

a³ + 27

= a³ + 3³

= (a + 3)(a² - 3a + 9)

comparing a² - 3a + 9 to a² + ma + 9, then

m = - 3

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!