The amount of rainfall in january in a certain city is normally distributed with a mean of 3.7 inches and a standard deviation of 0.5 find the value of q1

x = 3.4

Step-by-step explanation:

given,                                  

mean = 3.7 inches                      

standard deviation =  0.5                  

we want find the value of Q₁ = ?                              

the value of x such that, P(X < x)= 0.25                                

= >

= >                      

=>                

=>                        

=> x = -0.67 x 0.5 + 3.7                

=> x = 3.365                      

=> x = 3.4

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: