What is the equation in slope-intercept form of the line that passes through the point (2,-2) and is perpendicular to the line represented by y = 2/5 x + 2

y = - x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x + 2 ← is in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - , thus

y = - x + c ← is the partial equation

To find c substitute (2, - 2) into the partial equation

- 2 = - 5 + c ⇒ c = - 2 + 5 = 3

y = - x + 3 ← equation of line

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

probably the last option

step-by-step explanation: