4. write the equation of the line that is parallel to the line y=-3x+4 that goes
through the point (9,-6).

Y =

Step-by-step explanation:

Given equation of first line as

Y = -3X + 4

Slop of the first line (m1) = -3

As first line is parallel to second line , then (m1) × (m2) = - 1

i.e m2 =

m2 =

m2 =

Now equation of seconf line with points (9 , -6) and slop

i.e equation of new line Y - y1 = m2 (X - x1)

                                       Y + 6=

Y =

Hence equation of new line is

Y =    Answer

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

oof

step-by-step explanation: