My number has a tens digit that is 8 more than the ones digits .zero is not one of my digits .

91

Step-by-step explanation:

Let the tens digit of my number is x and the ones digit is y.

Hence, the number is 10x + y (1)

Now, it is given that, the ones digit is 8 less than the tens digit,

Hence, x = y + 8 (2)

Since the digits x and y can not be of two-digit i.e. they are less than 10 and x and y none of them can be zero, then fro equation (2), the only combination of x and y are 9 and 1.

Therefore, the number is ( 10 × 9) + 1 = 91. (Answer)

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

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step-by-step explanation:

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