Find the value of x in each case:

pu ∩ rt = s, q ∈ pr

x=34

Step-by-step explanation:

When we look triangle SQR, we have angles 3x and 68, we know that sum angles of triangle is 180.

<R=180-(3x+68)

Now, we look at the PQS:

<PQS=180-68=112°

Then :

<PSQ=180-(112+x)=68-x

Then we have :

Angles PSR= 68-x+3x=68+2x and angles TSU=4x.

We have that

PSR=TSU

68+2x=4x

4x-2x=68

2x=68

x=34

450

step-by-step explanation:

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