Ja'von kicks a soccer ball into the air. the function f(x) = –16(x – 2)2 + 64 represents the height of the ball, in feet, as a function of time, x, in seconds. what is the maximum height the ball reaches?

2feet

16 feet

32 feet

64 feet

Option D - 64 feet.

Step-by-step explanation:

Given : Ja'Von kicks a soccer ball into the air. The function represents the height of the ball, in feet, as a function of time, x, in seconds.

To find: What is the maximum height the ball reaches?

Solution :

To find the maximum height of the ball we find the derivative,

Derivate w.r.t x

To find maxima put

Now, we find the second derivative form maximum,

Therefore, The maximum point is at x=2

Substitute x=2 in the given function,

Therefore, Option D is correct.    

The maximum height the ball reaches is 64 feet.                      

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w