Mathematics, 27.10.2019 22:43 girdwood797
Write the equation of the line that passes through the vertex of the parabola y=-2x^2+12x-11 and the point (-2,47)
Answers: 1
![\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{+12}x\stackrel{\stackrel{c}{\downarrow }}{-11} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{12}{2(-2)}~~,~~-11-\cfrac{12^2}{4(-2)} \right)\implies \left( 3~~,~~-11+\cfrac{144}{8} \right) \\\\\\ (3~~,~~-11+18)\implies (3~~,~~7) \\\\[-0.35em] ~\dotfill](/tpl/images/0348/7359/add1e.png)
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Write the equation of the line that passes through the vertex of the parabola y=-2x^2+12x-11 and the...
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