Find the slope of the line tangent to the graph of y = sin- 1 x at
x = 0.

1.

Step-by-step explanation:

First find the derivative of sin-1x.

This is a standard derivative and it is  1 /√(1 - x^2)

This is the slope of the graph at  x.

Slope at x = 0  = 1 /√(1 - 0^2)

= 1/1 = 1,

i need a picture

step-by-step explanation:

what is the original number? you forgot to add it.