Ihope this image is clearer than the last.

10 to the power of 250

Step-by-step explanation:

i have no clue it is a guess

1.B)  and 2. A)

Step-by-step explanation:

1.This question is very interesting

Only by this statement, the question can be solved

f(x)=ax3−ax2+bx+4 is a multiple of x2+1;

Because the roots of the equation x2+1 would be the roots of f(x).

Therefore if j,k are roots of the equation then j+k=0 and j.k=1. Let the roots of f(x) be j,k,l.

Then,

j+k+l=−−aa

l=1

now, j.k.l=−4a

so, a=−4

now j.k+l(k+j)=b−4

Therefore b=−4

Finally a+b=−8

But f(4)=4(−43+42−4+1)

Therefore f(4)=−204

So the question may be incorrect.

2.The vertex of a parabola is at x = -b/2a

your equation is:

-14x^2 + bx + c = y

This equation is in standard form when y = 0.

We get:

-14x^2 + bx + c = 0

a = -14

b and c are unknown.

Equation for the vertex is x = -b/2a

We know that we want the vertex at (6,0), so we are at the vertex when:

x = 6

y = 0

substituting x = 6 in the equation for the vertex, we get:

6 = -b/2a

We know that a = -14, so this equation becomes:

6 = -b/(-28)

We solve for b to get:

b = 168

Our equation now becomes:

-14x^2 + 168x + c = y

We know that the vertex is at (6,0) so we know that we want this equation to equal to 0 at the point x = 6.

We set y = 0 and we substitute 6 for x in the equation to get:

-14*(6^2) + 168(6) + c = 0

This becomes:

-504 + 1008 + c = 0

Thie becomes:

504 + c = 0

we solve for c to get:

c = -504

Our equation becomes:

y = -14x^2 + 168x - 504

Answer to your question is:

b = 168

c = -504

Graph of this equation is shown below:  

Because a is negative, this graph opens downward.

If a was positive, it would open upward.

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)