What is the approximate length of the hypotenuse of a right triangle with vertices (-6, 2),
(6,-3) and (-6, -3)?

Step-by-step explanation:

A(-6, 2),   B(6,-3) and C(-6, -3)

AB² =  (x₂ - x₁)² + (y₂ - y₁)²

      = ( 6 -[-6])² + ( -3 -2)²

      = ( 6 + 6)² + ( -3 -2)² = 12²  + (-5)²  = 144 + 25 =169

AB = √169 = 13 units

BC²  = ( -6 -6)²  + ( -3 - [-3])² = (-6-6)²  + (-3 +3)²

      = (-12)²  + 0  = 144

BC = √144 = 12 unis

CA²  = (-6 - [-6])²  +(-3-2)²  = (-6 + 6)²  + ( -3-2)²

         = 0 + (-5)²  = 25

CA =√25 = 5 units

length of the hypotenuse of a right triangle  = 13units

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

the olimpics is not going to wokk out

step-by-step explanation: