Find the equation of a line which passes through the point (3, -1) with the gradient m=2÷3

Step-by-step explanation:

Equ of line -

y=mx+c

Using point (3,-1)

3 as x, - 1 as y

M=2/3

Substitute the values of these coordinates

3=2/3(-1) +c - - - - now find for c

c= 3- (-2/3)

c= 3.67

Now with the value of c, put the values back into the equation form .. Assuming we don't have a point to work with

y=2/3x + 3.67

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!