2. the equation (2x-3)(x+7)=0 has a solution set of
(1) {-7,11)
(3) {-7,3}
(2) {3, 7}
(4) {1/2,-3}

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places