Find the area under the standard normal probability distribution between the following pairs of z-scores. a. zequals0 and zequals1.00 e. zequalsminus1.00 and zequals0 b. zequals0 and zequals2.00 f. zequalsminus2.00 and zequals0 c. zequals0 and zequals3.00 g. zequalsnegative 1.49 and zequals0 d. zequals0 and zequals0.82 h. zequalsminus0.82 and zequals0

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Step-by-step explanation:

All this values can be easily found by using a table or a spreadsheet.

a)

P(0 ≤ z ≤ 1) = 0.3413

e)

P(-1 ≤ z ≤ 0) = P(0 ≤ z ≤ 1) = 0.3413 because N(0;1) is symmetrical

b)

P(0 ≤ z ≤ 2) = 0.4772

f)

P(-2 ≤ z ≤ 0) = P(0 ≤ z ≤ 2) = 0.4772

c)

P(0 ≤ z ≤ 3) = 0.4987

g)

P(-1.49 ≤ z ≤ 0) = 0.4319

d)

P(0 ≤ z ≤ 0.82) = 0.2939

h)

P(-0.82 ≤ z ≤ 0) = P(0 ≤ z ≤ 0.82) = 0.2939

me

step-by-step explanation:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: