Sam has twice as many dimes as quarters and two less nickels than dimes. if sam has a total of$ 5.40. if sam has a total of 5.40, how many of each coin does he have if sam has a total of $ 5.40.

Quarters=10 coins

Dimes= 20 coins

Nickels=18 coins

Step-by-step explanation:

a). Find how many of each coin he has.

Let the number of quarters he has=x, number of dimes is twice that of quarters=(2×x)=2x, number of nickels is 2 less than dimes=2x-2

So the number of each coin can be expressed as;

Quarters=x

Dimes=2x

Nickels=2x-2

b). Value of each coin

c). Total value for all the coins

Total value of Sams coins=Total value of Quarters+Total value of Dimes+Total value of Nickels

Replacing;

5.4=(0.25x+0.20x+0.1x)-0.1

5.4=0.55x-0.1

0.55x=5.4+0.1

0.55x/0.55=5.5/0.55

x=10

d). Replacing to get the number of each coin Sam has

Quarters=x=10 coins

Dimes=2x=(2×10)=20 coins

Nickels=2x-2=(2×10)-2=18 coins

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116