Chain emails are emails with a message suggesting you will have good luck if you forward the email on to others.
suppose a student started a chain email by sending the message to 3 friends and asking those friends to each send the
same email to 3 more friends exactly 1 day after receiving it.
b. which day is the first day that the number of people receiving the email exceeds 100?

b.

starts with student-day one

3*3=9-day two

9*3=27-day three

27*3=81-day four

81*3= over 100- day five

it's day 5 unless you count the first student sending the message as day 0, if so then your answer is day 4

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)