The equations that must be solved for maximum or minimum values of a differentiable function wequalsf(x, y,z) subject to two constraints g(x, y,z)equals0 and h(x, y,z)equals0, where g and h are also differentiable, are h, g(x, y,z)equals0, and h(x, y,z)equals0, where lambda and mu (the lagrange multipliers) are real numbers. use this result to find the point closest to the origin in the line of intersection l of the planes x plus 2 z equals 24 and x plus y equals 12.

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go to quizlet its really

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we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

b if for most of the graph

d if y intercept

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