Discuss the similarities and the differences between the empirical rule and chebychev's theorem what is a similarity between the empirical rule and chebychev's theorem? 0 a. o b. ° c. both apply only to symmetric and bell-shaped distributions. both do not require the data to have a sample standard deviation. both calculate the variance and standard deviation of a sample. d. both estimate proportions of the data contained within k standard deviations of the mean what is a difference between the empirical rule and chebychev's theorem? a. the empirical rule assumes the distribution is aproximately symmetric and bell-shaped and chebychev's theorem makes no assumptions o b. chebychev's theorem estimates proportions of data contained within infinite standard deviations and the empirical rule has a limit of 5 standard deviations ° c. the empirical rule assumes a small data set (less than 50 values) where chebychev's theorem has no limit on data size. o d. chebychev's theorem applies only to distributions which are approximately symmetric or bell-shaped and the empirical theorem has no restrictions.

1. Option C

2. Option A

Step-by-step explanation:

We are given the following information in the question:

1. Similarity between the Empirical Rule and Chebychev's Theorem:

Both Empirical Rule and Chebychev's Theorem,  helps us to determine the percentage of data lying within the standard deviations from the mean value.

Hence, similarity is given by:

Option C)  Both calculate the variance and standard deviation of a sample.

2. Difference between the Empirical Rule and Chebychev's Theorem:

Empirical rule is applicable for normally distributed data and Chebychev's Theorem can be applied to any data.

Hence, the difference is given by:

Option A) The Empirical Rule assumes the distribution is approximately symmetric and bell-shaped and Chebychev's Theorem makes no assumptions.

0.85% : )

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)