If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at random (assume the child may write the same letter twice), what is the probability that one is a vowel and the other is a consonant?

Step-by-step explanation:

In probability

Here, we want P(vowel) "AND" P(consonant). So we find individual probabilities and "MULTIPLY" them.

Firstly, P(vowel):

From the letters  a,b,c,i,e ------  we know 2 are vowel and 3 are consonants (total 5)

Hence, P(vowel) = 2/5

Second, P(consonant):

There are 3 consonants, hence

P(consonant) = 3/5

Now, we multiply:

P(vowel and consonant) = P(vowel) * P(consonant) = 2/5 * 3/5 = 6/25

The probability that one is vowel and the other is a consonant =

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation: