The width of a rectangle is 2/5 its length. find the dimensions if the perimeter is 42
meters.

The formula to find the perimeter of a rectangle is P= 2(l+w). By substituting what we now knowin to the equation:

•42=2(l+(2/5l)). We can have width represented at (2/5l) because it’s now 2/5 of the length. Now add them together to get a single coefficient for l.

•42= 2(7/5l). Multiplying 7/5 by 2.

42= (14/5l). Multiplying both sides by the reciprocal of 14/5, which is 5/14, to get l by itself.

•l= 15.

Now that we now know the value of l, we know that the length is 15m. To find the width of the answer, we then multiply 15 by 2/5, which equals 6. Therefore, the only third option is correct because the length is 15m and the width is 6m.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

answer: a and b

step-by-step explanation: