Consider a sequence that follows a times 5 pattern: 1, 5, 25, 125, ….
a. write a formula for the nnth term of the sequence. be sure to specify what value of n your formula starts with.

Hello mate!

Here we have the sequence: 1, 5, 25, 125, etc

the first term is an 1 = 5^0

the second term is 5 = 5^1

the third term is 25 = (5*5) = 5^2

the fourth term is 125 = 5*25 = (5*5*5) = 5^3

then the n-th term is five to the power of (n - 1)

The n-th term of the sequence is:

p(n) = 5^(n-1)

and the recursive relation is:

p(n) = 5p(n-1)

where p(1) = 1

where n ≥ 1

hard

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.