Jerry has thought of a pattern that shows powers of two. here are the first six numbers of jerry’s sequence:
1, 2, 4, 8, 16, 32, ….
write an expression for the nth number of jerry’s sequence.

nth number of Jerry’s sequence = 2ⁿ⁻¹

Step-by-step explanation:

This is an example of geometric progression.

First term, a = 1

Common ratio, r = 2

We have expression for n th term of GP as

Substituting

nth number of Jerry’s sequence = 2ⁿ⁻¹