Find 4 consecutive odd numbers whose sum is 456

plz : ')

4 consecutive odd numbers are 111, 113, 115 and 117.

Step-by-step explanation:

Let the first odd number be x.

So the next odd number will be (x+2)

and the next  two consecutive odd numbers are (x+ 4) and (x+6)

According to question,

The sum of all four odd consecutive numbers = 456

⇒ x +  (x+ 2) +  (x+4) +  (x+6)  = 456

or, 4x + 12 = 456

⇒ 4x = 456 - 12 = 444

⇒ x = 444/4 =  111

Hence, the first odd number = 111

Second odd number = 111+ 2 = 113

Third odd number is x + 4 = 111 + 4 = 115

And last odd number is x + 6 = 111 + 6 = 117

So, 4 consecutive odd numbers are 111, 113, 115 and 117.

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step-by-step explanation:

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i believe the answer is c.