Suppose that 48% of the women who gave birth at a certain hospital last year were over 30 years old, and that 46% were unmarried. if 65% of the women were over 30 or unmarried (or both), what is the probability that a woman who gave birth at the hospital was both unmarried and over 30 ?

0.29 (29%)

Step-by-step explanation:

women who gave birth at a certain hospital last year:

over 30 years old - 0.48

unmarried - 0.46

over 30 or unmarried (or both) - 0.65

what is the probability that a woman who gave birth at the hospital was both unmarried and over 30 ?

We know that

P(A and B) = P(A) + P(B) - P(A or B)

P(+30 and unmarried) = P(+30) + P(unmarried) - P(+30 or unmarried)

P(+30 and unmarried) = 0.48 + 0.46 - 0.65 = 0.29

b

step-by-step explanation:

answer is (b.

164 ft2)

a base  

18

b base  

7

h height  

8