with working what’s the values of a b and c

(2x+1)(ax+b)=(6x^2-5x+c)

Step-by-step explanation:

(2x + 1)(ax + b) = 6x² - 5x + c

Expand the left side and put that half into standard form:

2ax² + 2bx + ax + b = 6x² - 5x + c

2ax² + (2b + a)x + b = 6x² - 5x + c

So now look at the x terms. We have "2a" x² on left and 6 x² on right, so:

2a = 6

a = 3

Then look at the x terms, those coefficients will then be equal:

2b + a = -5

2b + 3 = -5

2b = -8

b = -4

and finally, then non-x terms are equal:

b = c

-4 = c

so:

a = 3, b = -4, c = -4

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn