Thirty percent of all telephones of a certain type are submitted for service while under warranty. of these, 70% can be repaired, whereas the other 30% must be replaced with new units. if a company purchases ten of these telephones, what is the probability that exactly three will end up being replaced under warranty? (round your answer to three decimal places.)

0.2669~0.267

Step-by-step explanation:

Given that Thirty percent of all telephones of a certain type are submitted for service while under warranty.

Let x be the no of units being replaced out of 10 units purchased by a company under warranty

We have X has two outcomes either replaced or not.  Also each unit is independent of the other

P(each unit fails and requires replaement ) = p =0.3

q =0.7

the probability that exactly three will end up being replaced under warranty

=P(X=3)

= ~0.267

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

the barter