During finals week, students arrive randomly at the desk of the computer lab. there is only one technician due to budget cuts, and the time required to provide service varies from student to student. the average arrival rate is 15 students per hour, and the average service rate is 20 students per hour. assuming standard waiting line distribution parameters hold. the administration finally increases the budget for the computer lab after numerous student protests, and the lab hires another technician who works at the same rate as the first technician. what is the average waiting time per student with the 2 technicians working at the same time? assume the students form a single line at the desk, and continue to arrive at the average rate of 15/hr.

what are you trying find out?

step-by-step explanation:

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.

b.

step-by-step explanation:

i just know

i believe it is the square root of 122 because when you turn it on it's side, to where the 5 inches is on the bottom, it looks like it is the same length.