Alaboratory technician needs to make a 36-liter batch of a 40% acid solution. how can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired concentration?

12 liters of pure acid with 24 liters of 10% acid solution

Step-by-step explanation:

Let us assume that x liters of pure acid is mixed with y liters of 10% acis solution.

Therefore, x+y =36 liters ....... (1)

Again the resulting acis solution is of 40% concentration.

Hence,

⇒ x+0.1y =0.4x +0.4y

⇒ 0.6x =0.3y

⇒ 2x =y .....(2)

Now, solving equations (1) and (2) we get,

3x =36, ⇒ x= 12 liters

And, from equation (2), we get y=2×12 =24 liters.

Therefore, the technician has to mix 12 liters of pure acid with 24 liters of 10% acid solution to get the requires solution. (Answer)

your answer would be 10x - 1

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)