Achemist has two solutions: a 50% methane solution and an 80% methane solution. he wants 100 ml of a 70% methane solution. how many ml of each solution does he need to mix?

33.33 mL of 50%

66.67 of 80%

Step-by-step explanation:

Let x = quantity of 50% methane.

Then,

0.50x + 0.80(100 - x) = 100 × 0.70

⇒ 0.50 x + 80 - 0.80 x = 70

⇒ -0.30 x = 70 - 80

⇒ -0.30 x = -10

⇒

⇒ x = 33.33 mL of 50%

and, 100 - 33.33 = 66.67 of 80%

for the points! : )

the answer is b i just did that

step-by-step explanation: