Find consecutive integers that are under and over estimates of the solutions to the following exponential equations.
10^x = 432,901

5 and 6

Step-by-step explanation:

We have to first solve the given equation

Now, taking log in the both sides we get,

⇒ x log 10=log 432901 {Since we have the logarithm property, log aᵇ =b log a}

⇒ x =log 432901 {Since log 10=1}

⇒ x=5.636.

Therefore, the consecutive integers that are under and over the value of x are 5 and 6. (Answer)

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this