Find the square rots of −5. show that the square rots satisfy the equation x2 + 5 = 0.

The square roots satisfies the equation

Step-by-step explanation:

As the square root of negative 1 is not real it is denoted by

In the given equation

So, the square roots satisfies the equation.

The root of -5 is +√5i and -√5i.

Step-by-step explanation:

Given data in the question is -5.

To find:-

Square roots of -5.

Solution:-

⇒±√-5

⇒±√5*√-1

⇒±√5i        (√-1=i(iota)

Given Equation

and and

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by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

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