The converse of the pythagorean theorem is also a theorem: if the square of one side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle. use the converse of the pythagorean theorem to show that for a, b, c > 0, if a +b = c, then √a+√b> √c, so that √a+√b> √(a+b)

11

step-by-step explanation:

32.50-7.50=25

225/25=11

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step-by-step explanation:

its line 2 i just added the rest or else it wouldn't let me answer

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0