Mathematics, 20.10.2019 20:30 tiaharris3191
Solve the differential equation y" + 3y' + 2y = p1 where, y" = d2y/dx2, y' = dy/dx, p1 = p1(x)) and the initial conditions are y(0) = 0, y'(0) = 0. the input function is given by p1() = { 0, < 0 1, 0 ≤ ≤ 1 0, > 1
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Solve the differential equation y" + 3y' + 2y = p1 where, y" = d2y/dx2, y' = dy/dx, p1 = p1(x)) and...
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