Which statement is true concerning the vertex and the axis of symmetry of g(x)=5x2-10x?
the function written in vertex form is g(x)=5(x-1)2-5. the vertex is at (1, -5) and the axis of symmetry is x=1.
the vertex is at (1,-5) and the axis of symmetry is y = 1.
the vertex is at (0,0) and the axis of symmetry is x = 1.
the vertex is at (0,0) and the axis of symmetry is y = 1.

x =1 & vertex is (1,-5)

Step-by-step explanation:

differentiate the equation with respect to 'x' and equate it to zero

we get

10(x-1)=0

x= 1

substitute in main equation

we get g(x) = -5

so the point is (1,-5)

*(this is the simplest way to find vertex of a parabola)

don't know differentiation?

then you have to convert the equation into standard form

(x-h)²= 4a(y-k)

(h,k) is vertex

The vertex is at (1,-5) and the axis of symmetry is y=1

Step-by-step explanation:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3